Integrand size = 32, antiderivative size = 322 \[ \int \frac {(a+b x)^2 \left (A+B x+C x^2+D x^3\right )}{(c+d x)^{5/2}} \, dx=-\frac {2 (b c-a d)^2 \left (c^2 C d-B c d^2+A d^3-c^3 D\right )}{3 d^6 (c+d x)^{3/2}}-\frac {2 (b c-a d) \left (a d \left (2 c C d-B d^2-3 c^2 D\right )-b \left (4 c^2 C d-3 B c d^2+2 A d^3-5 c^3 D\right )\right )}{d^6 \sqrt {c+d x}}+\frac {2 \left (a^2 d^2 (C d-3 c D)-2 a b d \left (3 c C d-B d^2-6 c^2 D\right )+b^2 \left (6 c^2 C d-3 B c d^2+A d^3-10 c^3 D\right )\right ) \sqrt {c+d x}}{d^6}+\frac {2 \left (a^2 d^2 D+2 a b d (C d-4 c D)-b^2 \left (4 c C d-B d^2-10 c^2 D\right )\right ) (c+d x)^{3/2}}{3 d^6}+\frac {2 b (b C d-5 b c D+2 a d D) (c+d x)^{5/2}}{5 d^6}+\frac {2 b^2 D (c+d x)^{7/2}}{7 d^6} \]
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Time = 0.16 (sec) , antiderivative size = 322, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.031, Rules used = {1634} \[ \int \frac {(a+b x)^2 \left (A+B x+C x^2+D x^3\right )}{(c+d x)^{5/2}} \, dx=\frac {2 \sqrt {c+d x} \left (a^2 d^2 (C d-3 c D)-2 a b d \left (-B d^2-6 c^2 D+3 c C d\right )+b^2 \left (A d^3-3 B c d^2-10 c^3 D+6 c^2 C d\right )\right )}{d^6}+\frac {2 (c+d x)^{3/2} \left (a^2 d^2 D+2 a b d (C d-4 c D)-\left (b^2 \left (-B d^2-10 c^2 D+4 c C d\right )\right )\right )}{3 d^6}-\frac {2 (b c-a d) \left (a d \left (-B d^2-3 c^2 D+2 c C d\right )-b \left (2 A d^3-3 B c d^2-5 c^3 D+4 c^2 C d\right )\right )}{d^6 \sqrt {c+d x}}-\frac {2 (b c-a d)^2 \left (A d^3-B c d^2+c^3 (-D)+c^2 C d\right )}{3 d^6 (c+d x)^{3/2}}+\frac {2 b (c+d x)^{5/2} (2 a d D-5 b c D+b C d)}{5 d^6}+\frac {2 b^2 D (c+d x)^{7/2}}{7 d^6} \]
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Rule 1634
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {(-b c+a d)^2 \left (c^2 C d-B c d^2+A d^3-c^3 D\right )}{d^5 (c+d x)^{5/2}}+\frac {(b c-a d) \left (a d \left (2 c C d-B d^2-3 c^2 D\right )-b \left (4 c^2 C d-3 B c d^2+2 A d^3-5 c^3 D\right )\right )}{d^5 (c+d x)^{3/2}}+\frac {a^2 d^2 (C d-3 c D)-2 a b d \left (3 c C d-B d^2-6 c^2 D\right )+b^2 \left (6 c^2 C d-3 B c d^2+A d^3-10 c^3 D\right )}{d^5 \sqrt {c+d x}}+\frac {\left (a^2 d^2 D+2 a b d (C d-4 c D)-b^2 \left (4 c C d-B d^2-10 c^2 D\right )\right ) \sqrt {c+d x}}{d^5}+\frac {b (b C d-5 b c D+2 a d D) (c+d x)^{3/2}}{d^5}+\frac {b^2 D (c+d x)^{5/2}}{d^5}\right ) \, dx \\ & = -\frac {2 (b c-a d)^2 \left (c^2 C d-B c d^2+A d^3-c^3 D\right )}{3 d^6 (c+d x)^{3/2}}-\frac {2 (b c-a d) \left (a d \left (2 c C d-B d^2-3 c^2 D\right )-b \left (4 c^2 C d-3 B c d^2+2 A d^3-5 c^3 D\right )\right )}{d^6 \sqrt {c+d x}}+\frac {2 \left (a^2 d^2 (C d-3 c D)-2 a b d \left (3 c C d-B d^2-6 c^2 D\right )+b^2 \left (6 c^2 C d-3 B c d^2+A d^3-10 c^3 D\right )\right ) \sqrt {c+d x}}{d^6}+\frac {2 \left (a^2 d^2 D+2 a b d (C d-4 c D)-b^2 \left (4 c C d-B d^2-10 c^2 D\right )\right ) (c+d x)^{3/2}}{3 d^6}+\frac {2 b (b C d-5 b c D+2 a d D) (c+d x)^{5/2}}{5 d^6}+\frac {2 b^2 D (c+d x)^{7/2}}{7 d^6} \\ \end{align*}
Time = 0.36 (sec) , antiderivative size = 317, normalized size of antiderivative = 0.98 \[ \int \frac {(a+b x)^2 \left (A+B x+C x^2+D x^3\right )}{(c+d x)^{5/2}} \, dx=\frac {-70 a^2 d^2 \left (16 c^3 D-8 c^2 d (C-3 D x)+2 c d^2 (B+3 x (-2 C+D x))+d^3 \left (A+3 B x-x^2 (3 C+D x)\right )\right )+28 a b d \left (128 c^4 D+c^3 (-80 C d+192 d D x)+8 c^2 d^2 (5 B+3 x (-5 C+2 D x))+d^4 x \left (-15 A+x \left (15 B+5 C x+3 D x^2\right )\right )-2 c d^3 \left (5 A+x \left (-30 B+15 C x+4 D x^2\right )\right )\right )+2 b^2 \left (-1280 c^5 D+128 c^4 d (7 C-15 D x)-16 c^3 d^2 (35 B+6 x (-14 C+5 D x))+d^5 x^2 (105 A+x (35 B+3 x (7 C+5 D x)))+8 c^2 d^3 (35 A+x (-105 B+2 x (21 C+5 D x)))-2 c d^4 x (-210 A+x (105 B+x (28 C+15 D x)))\right )}{105 d^6 (c+d x)^{3/2}} \]
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Time = 1.73 (sec) , antiderivative size = 288, normalized size of antiderivative = 0.89
method | result | size |
pseudoelliptic | \(-\frac {2 \left (\left (\left (-\frac {3}{7} D x^{5}-\frac {3}{5} C \,x^{4}-3 A \,x^{2}-x^{3} B \right ) b^{2}+6 a x \left (-\frac {1}{5} D x^{3}-\frac {1}{3} C \,x^{2}-B x +A \right ) b +a^{2} \left (-D x^{3}-3 C \,x^{2}+3 B x +A \right )\right ) d^{5}+4 \left (-3 x \left (-\frac {1}{14} D x^{3}-\frac {2}{15} C \,x^{2}-\frac {1}{2} B x +A \right ) b^{2}+a \left (\frac {4}{5} D x^{3}+3 C \,x^{2}-6 B x +A \right ) b +\frac {a^{2} \left (3 D x^{2}-6 C x +B \right )}{2}\right ) c \,d^{4}-8 \left (\left (\frac {2}{7} D x^{3}+\frac {6}{5} C \,x^{2}-3 B x +A \right ) b^{2}+2 a \left (\frac {6}{5} D x^{2}-3 C x +B \right ) b +a^{2} \left (-3 D x +C \right )\right ) c^{2} d^{3}+16 c^{3} \left (\left (\frac {6}{7} D x^{2}-\frac {12}{5} C x +B \right ) b^{2}+2 \left (-\frac {12 D x}{5}+C \right ) a b +D a^{2}\right ) d^{2}-\frac {128 \left (\left (-\frac {15 D x}{7}+C \right ) b +2 D a \right ) b \,c^{4} d}{5}+\frac {256 D b^{2} c^{5}}{7}\right )}{3 \left (d x +c \right )^{\frac {3}{2}} d^{6}}\) | \(288\) |
gosper | \(-\frac {2 \left (-15 D b^{2} x^{5} d^{5}-21 C \,b^{2} d^{5} x^{4}-42 D a b \,d^{5} x^{4}+30 D b^{2} c \,d^{4} x^{4}-35 B \,b^{2} d^{5} x^{3}-70 C a b \,d^{5} x^{3}+56 C \,b^{2} c \,d^{4} x^{3}-35 D a^{2} d^{5} x^{3}+112 D a b c \,d^{4} x^{3}-80 D b^{2} c^{2} d^{3} x^{3}-105 A \,b^{2} d^{5} x^{2}-210 B a b \,d^{5} x^{2}+210 B \,b^{2} c \,d^{4} x^{2}-105 C \,a^{2} d^{5} x^{2}+420 C a b c \,d^{4} x^{2}-336 C \,b^{2} c^{2} d^{3} x^{2}+210 D a^{2} c \,d^{4} x^{2}-672 D a b \,c^{2} d^{3} x^{2}+480 D b^{2} c^{3} d^{2} x^{2}+210 A a b \,d^{5} x -420 A \,b^{2} c \,d^{4} x +105 B \,a^{2} d^{5} x -840 B a b c \,d^{4} x +840 B \,b^{2} c^{2} d^{3} x -420 C \,a^{2} c \,d^{4} x +1680 C a b \,c^{2} d^{3} x -1344 C \,b^{2} c^{3} d^{2} x +840 D a^{2} c^{2} d^{3} x -2688 D a b \,c^{3} d^{2} x +1920 D b^{2} c^{4} d x +35 a^{2} A \,d^{5}+140 A a b c \,d^{4}-280 A \,b^{2} c^{2} d^{3}+70 B \,a^{2} c \,d^{4}-560 B a b \,c^{2} d^{3}+560 B \,b^{2} c^{3} d^{2}-280 C \,a^{2} c^{2} d^{3}+1120 C a b \,c^{3} d^{2}-896 C \,b^{2} c^{4} d +560 D a^{2} c^{3} d^{2}-1792 D a b \,c^{4} d +1280 D b^{2} c^{5}\right )}{105 \left (d x +c \right )^{\frac {3}{2}} d^{6}}\) | \(505\) |
trager | \(-\frac {2 \left (-15 D b^{2} x^{5} d^{5}-21 C \,b^{2} d^{5} x^{4}-42 D a b \,d^{5} x^{4}+30 D b^{2} c \,d^{4} x^{4}-35 B \,b^{2} d^{5} x^{3}-70 C a b \,d^{5} x^{3}+56 C \,b^{2} c \,d^{4} x^{3}-35 D a^{2} d^{5} x^{3}+112 D a b c \,d^{4} x^{3}-80 D b^{2} c^{2} d^{3} x^{3}-105 A \,b^{2} d^{5} x^{2}-210 B a b \,d^{5} x^{2}+210 B \,b^{2} c \,d^{4} x^{2}-105 C \,a^{2} d^{5} x^{2}+420 C a b c \,d^{4} x^{2}-336 C \,b^{2} c^{2} d^{3} x^{2}+210 D a^{2} c \,d^{4} x^{2}-672 D a b \,c^{2} d^{3} x^{2}+480 D b^{2} c^{3} d^{2} x^{2}+210 A a b \,d^{5} x -420 A \,b^{2} c \,d^{4} x +105 B \,a^{2} d^{5} x -840 B a b c \,d^{4} x +840 B \,b^{2} c^{2} d^{3} x -420 C \,a^{2} c \,d^{4} x +1680 C a b \,c^{2} d^{3} x -1344 C \,b^{2} c^{3} d^{2} x +840 D a^{2} c^{2} d^{3} x -2688 D a b \,c^{3} d^{2} x +1920 D b^{2} c^{4} d x +35 a^{2} A \,d^{5}+140 A a b c \,d^{4}-280 A \,b^{2} c^{2} d^{3}+70 B \,a^{2} c \,d^{4}-560 B a b \,c^{2} d^{3}+560 B \,b^{2} c^{3} d^{2}-280 C \,a^{2} c^{2} d^{3}+1120 C a b \,c^{3} d^{2}-896 C \,b^{2} c^{4} d +560 D a^{2} c^{3} d^{2}-1792 D a b \,c^{4} d +1280 D b^{2} c^{5}\right )}{105 \left (d x +c \right )^{\frac {3}{2}} d^{6}}\) | \(505\) |
derivativedivides | \(\frac {\frac {2 D b^{2} \left (d x +c \right )^{\frac {7}{2}}}{7}+\frac {2 C \,b^{2} d \left (d x +c \right )^{\frac {5}{2}}}{5}+\frac {4 D a b d \left (d x +c \right )^{\frac {5}{2}}}{5}-2 D b^{2} c \left (d x +c \right )^{\frac {5}{2}}+\frac {2 B \,b^{2} d^{2} \left (d x +c \right )^{\frac {3}{2}}}{3}+\frac {4 C a b \,d^{2} \left (d x +c \right )^{\frac {3}{2}}}{3}-\frac {8 C \,b^{2} c d \left (d x +c \right )^{\frac {3}{2}}}{3}+\frac {2 D a^{2} d^{2} \left (d x +c \right )^{\frac {3}{2}}}{3}-\frac {16 D a b c d \left (d x +c \right )^{\frac {3}{2}}}{3}+\frac {20 D b^{2} c^{2} \left (d x +c \right )^{\frac {3}{2}}}{3}+2 A \,b^{2} d^{3} \sqrt {d x +c}+4 B a b \,d^{3} \sqrt {d x +c}-6 B \,b^{2} c \,d^{2} \sqrt {d x +c}+2 C \,a^{2} d^{3} \sqrt {d x +c}-12 C a b c \,d^{2} \sqrt {d x +c}+12 C \,b^{2} c^{2} d \sqrt {d x +c}-6 D a^{2} c \,d^{2} \sqrt {d x +c}+24 D a b \,c^{2} d \sqrt {d x +c}-20 D b^{2} c^{3} \sqrt {d x +c}-\frac {2 \left (2 a b A \,d^{4}-2 A \,b^{2} c \,d^{3}+a^{2} B \,d^{4}-4 B a b c \,d^{3}+3 B \,b^{2} c^{2} d^{2}-2 C \,a^{2} c \,d^{3}+6 C a b \,c^{2} d^{2}-4 C \,b^{2} c^{3} d +3 D a^{2} c^{2} d^{2}-8 D a b \,c^{3} d +5 D b^{2} c^{4}\right )}{\sqrt {d x +c}}-\frac {2 \left (a^{2} A \,d^{5}-2 A a b c \,d^{4}+A \,b^{2} c^{2} d^{3}-B \,a^{2} c \,d^{4}+2 B a b \,c^{2} d^{3}-B \,b^{2} c^{3} d^{2}+C \,a^{2} c^{2} d^{3}-2 C a b \,c^{3} d^{2}+C \,b^{2} c^{4} d -D a^{2} c^{3} d^{2}+2 D a b \,c^{4} d -D b^{2} c^{5}\right )}{3 \left (d x +c \right )^{\frac {3}{2}}}}{d^{6}}\) | \(547\) |
default | \(\frac {\frac {2 D b^{2} \left (d x +c \right )^{\frac {7}{2}}}{7}+\frac {2 C \,b^{2} d \left (d x +c \right )^{\frac {5}{2}}}{5}+\frac {4 D a b d \left (d x +c \right )^{\frac {5}{2}}}{5}-2 D b^{2} c \left (d x +c \right )^{\frac {5}{2}}+\frac {2 B \,b^{2} d^{2} \left (d x +c \right )^{\frac {3}{2}}}{3}+\frac {4 C a b \,d^{2} \left (d x +c \right )^{\frac {3}{2}}}{3}-\frac {8 C \,b^{2} c d \left (d x +c \right )^{\frac {3}{2}}}{3}+\frac {2 D a^{2} d^{2} \left (d x +c \right )^{\frac {3}{2}}}{3}-\frac {16 D a b c d \left (d x +c \right )^{\frac {3}{2}}}{3}+\frac {20 D b^{2} c^{2} \left (d x +c \right )^{\frac {3}{2}}}{3}+2 A \,b^{2} d^{3} \sqrt {d x +c}+4 B a b \,d^{3} \sqrt {d x +c}-6 B \,b^{2} c \,d^{2} \sqrt {d x +c}+2 C \,a^{2} d^{3} \sqrt {d x +c}-12 C a b c \,d^{2} \sqrt {d x +c}+12 C \,b^{2} c^{2} d \sqrt {d x +c}-6 D a^{2} c \,d^{2} \sqrt {d x +c}+24 D a b \,c^{2} d \sqrt {d x +c}-20 D b^{2} c^{3} \sqrt {d x +c}-\frac {2 \left (2 a b A \,d^{4}-2 A \,b^{2} c \,d^{3}+a^{2} B \,d^{4}-4 B a b c \,d^{3}+3 B \,b^{2} c^{2} d^{2}-2 C \,a^{2} c \,d^{3}+6 C a b \,c^{2} d^{2}-4 C \,b^{2} c^{3} d +3 D a^{2} c^{2} d^{2}-8 D a b \,c^{3} d +5 D b^{2} c^{4}\right )}{\sqrt {d x +c}}-\frac {2 \left (a^{2} A \,d^{5}-2 A a b c \,d^{4}+A \,b^{2} c^{2} d^{3}-B \,a^{2} c \,d^{4}+2 B a b \,c^{2} d^{3}-B \,b^{2} c^{3} d^{2}+C \,a^{2} c^{2} d^{3}-2 C a b \,c^{3} d^{2}+C \,b^{2} c^{4} d -D a^{2} c^{3} d^{2}+2 D a b \,c^{4} d -D b^{2} c^{5}\right )}{3 \left (d x +c \right )^{\frac {3}{2}}}}{d^{6}}\) | \(547\) |
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Time = 0.29 (sec) , antiderivative size = 431, normalized size of antiderivative = 1.34 \[ \int \frac {(a+b x)^2 \left (A+B x+C x^2+D x^3\right )}{(c+d x)^{5/2}} \, dx=\frac {2 \, {\left (15 \, D b^{2} d^{5} x^{5} - 1280 \, D b^{2} c^{5} - 35 \, A a^{2} d^{5} + 280 \, {\left (C a^{2} + 2 \, B a b + A b^{2}\right )} c^{2} d^{3} - 70 \, {\left (B a^{2} + 2 \, A a b\right )} c d^{4} - 3 \, {\left (10 \, D b^{2} c d^{4} - 7 \, {\left (2 \, D a b + C b^{2}\right )} d^{5}\right )} x^{4} + {\left (80 \, D b^{2} c^{2} d^{3} + 35 \, {\left (D a^{2} + 2 \, C a b + B b^{2}\right )} d^{5} - 56 \, {\left (2 \, D a b c + C b^{2} c\right )} d^{4}\right )} x^{3} - 560 \, {\left (D a^{2} c^{3} + {\left (2 \, C a b + B b^{2}\right )} c^{3}\right )} d^{2} - 3 \, {\left (160 \, D b^{2} c^{3} d^{2} - 35 \, {\left (C a^{2} + 2 \, B a b + A b^{2}\right )} d^{5} + 70 \, {\left (D a^{2} c + {\left (2 \, C a b + B b^{2}\right )} c\right )} d^{4} - 112 \, {\left (2 \, D a b c^{2} + C b^{2} c^{2}\right )} d^{3}\right )} x^{2} + 896 \, {\left (2 \, D a b c^{4} + C b^{2} c^{4}\right )} d - 3 \, {\left (640 \, D b^{2} c^{4} d - 140 \, {\left (C a^{2} + 2 \, B a b + A b^{2}\right )} c d^{4} + 35 \, {\left (B a^{2} + 2 \, A a b\right )} d^{5} + 280 \, {\left (D a^{2} c^{2} + {\left (2 \, C a b + B b^{2}\right )} c^{2}\right )} d^{3} - 448 \, {\left (2 \, D a b c^{3} + C b^{2} c^{3}\right )} d^{2}\right )} x\right )} \sqrt {d x + c}}{105 \, {\left (d^{8} x^{2} + 2 \, c d^{7} x + c^{2} d^{6}\right )}} \]
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Time = 29.35 (sec) , antiderivative size = 476, normalized size of antiderivative = 1.48 \[ \int \frac {(a+b x)^2 \left (A+B x+C x^2+D x^3\right )}{(c+d x)^{5/2}} \, dx=\begin {cases} \frac {2 \left (\frac {D b^{2} \left (c + d x\right )^{\frac {7}{2}}}{7 d^{5}} + \frac {\left (c + d x\right )^{\frac {5}{2}} \left (C b^{2} d + 2 D a b d - 5 D b^{2} c\right )}{5 d^{5}} + \frac {\left (c + d x\right )^{\frac {3}{2}} \left (B b^{2} d^{2} + 2 C a b d^{2} - 4 C b^{2} c d + D a^{2} d^{2} - 8 D a b c d + 10 D b^{2} c^{2}\right )}{3 d^{5}} + \frac {\sqrt {c + d x} \left (A b^{2} d^{3} + 2 B a b d^{3} - 3 B b^{2} c d^{2} + C a^{2} d^{3} - 6 C a b c d^{2} + 6 C b^{2} c^{2} d - 3 D a^{2} c d^{2} + 12 D a b c^{2} d - 10 D b^{2} c^{3}\right )}{d^{5}} - \frac {\left (a d - b c\right ) \left (2 A b d^{3} + B a d^{3} - 3 B b c d^{2} - 2 C a c d^{2} + 4 C b c^{2} d + 3 D a c^{2} d - 5 D b c^{3}\right )}{d^{5} \sqrt {c + d x}} + \frac {\left (a d - b c\right )^{2} \left (- A d^{3} + B c d^{2} - C c^{2} d + D c^{3}\right )}{3 d^{5} \left (c + d x\right )^{\frac {3}{2}}}\right )}{d} & \text {for}\: d \neq 0 \\\frac {A a^{2} x + \frac {D b^{2} x^{6}}{6} + \frac {x^{5} \left (C b^{2} + 2 D a b\right )}{5} + \frac {x^{4} \left (B b^{2} + 2 C a b + D a^{2}\right )}{4} + \frac {x^{3} \left (A b^{2} + 2 B a b + C a^{2}\right )}{3} + \frac {x^{2} \cdot \left (2 A a b + B a^{2}\right )}{2}}{c^{\frac {5}{2}}} & \text {otherwise} \end {cases} \]
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Time = 0.21 (sec) , antiderivative size = 393, normalized size of antiderivative = 1.22 \[ \int \frac {(a+b x)^2 \left (A+B x+C x^2+D x^3\right )}{(c+d x)^{5/2}} \, dx=\frac {2 \, {\left (\frac {15 \, {\left (d x + c\right )}^{\frac {7}{2}} D b^{2} - 21 \, {\left (5 \, D b^{2} c - {\left (2 \, D a b + C b^{2}\right )} d\right )} {\left (d x + c\right )}^{\frac {5}{2}} + 35 \, {\left (10 \, D b^{2} c^{2} - 4 \, {\left (2 \, D a b + C b^{2}\right )} c d + {\left (D a^{2} + 2 \, C a b + B b^{2}\right )} d^{2}\right )} {\left (d x + c\right )}^{\frac {3}{2}} - 105 \, {\left (10 \, D b^{2} c^{3} - 6 \, {\left (2 \, D a b + C b^{2}\right )} c^{2} d + 3 \, {\left (D a^{2} + 2 \, C a b + B b^{2}\right )} c d^{2} - {\left (C a^{2} + 2 \, B a b + A b^{2}\right )} d^{3}\right )} \sqrt {d x + c}}{d^{5}} + \frac {35 \, {\left (D b^{2} c^{5} - A a^{2} d^{5} - {\left (2 \, D a b + C b^{2}\right )} c^{4} d + {\left (D a^{2} + 2 \, C a b + B b^{2}\right )} c^{3} d^{2} - {\left (C a^{2} + 2 \, B a b + A b^{2}\right )} c^{2} d^{3} + {\left (B a^{2} + 2 \, A a b\right )} c d^{4} - 3 \, {\left (5 \, D b^{2} c^{4} - 4 \, {\left (2 \, D a b + C b^{2}\right )} c^{3} d + 3 \, {\left (D a^{2} + 2 \, C a b + B b^{2}\right )} c^{2} d^{2} - 2 \, {\left (C a^{2} + 2 \, B a b + A b^{2}\right )} c d^{3} + {\left (B a^{2} + 2 \, A a b\right )} d^{4}\right )} {\left (d x + c\right )}\right )}}{{\left (d x + c\right )}^{\frac {3}{2}} d^{5}}\right )}}{105 \, d} \]
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Leaf count of result is larger than twice the leaf count of optimal. 622 vs. \(2 (302) = 604\).
Time = 0.30 (sec) , antiderivative size = 622, normalized size of antiderivative = 1.93 \[ \int \frac {(a+b x)^2 \left (A+B x+C x^2+D x^3\right )}{(c+d x)^{5/2}} \, dx=-\frac {2 \, {\left (15 \, {\left (d x + c\right )} D b^{2} c^{4} - D b^{2} c^{5} - 24 \, {\left (d x + c\right )} D a b c^{3} d - 12 \, {\left (d x + c\right )} C b^{2} c^{3} d + 2 \, D a b c^{4} d + C b^{2} c^{4} d + 9 \, {\left (d x + c\right )} D a^{2} c^{2} d^{2} + 18 \, {\left (d x + c\right )} C a b c^{2} d^{2} + 9 \, {\left (d x + c\right )} B b^{2} c^{2} d^{2} - D a^{2} c^{3} d^{2} - 2 \, C a b c^{3} d^{2} - B b^{2} c^{3} d^{2} - 6 \, {\left (d x + c\right )} C a^{2} c d^{3} - 12 \, {\left (d x + c\right )} B a b c d^{3} - 6 \, {\left (d x + c\right )} A b^{2} c d^{3} + C a^{2} c^{2} d^{3} + 2 \, B a b c^{2} d^{3} + A b^{2} c^{2} d^{3} + 3 \, {\left (d x + c\right )} B a^{2} d^{4} + 6 \, {\left (d x + c\right )} A a b d^{4} - B a^{2} c d^{4} - 2 \, A a b c d^{4} + A a^{2} d^{5}\right )}}{3 \, {\left (d x + c\right )}^{\frac {3}{2}} d^{6}} + \frac {2 \, {\left (15 \, {\left (d x + c\right )}^{\frac {7}{2}} D b^{2} d^{36} - 105 \, {\left (d x + c\right )}^{\frac {5}{2}} D b^{2} c d^{36} + 350 \, {\left (d x + c\right )}^{\frac {3}{2}} D b^{2} c^{2} d^{36} - 1050 \, \sqrt {d x + c} D b^{2} c^{3} d^{36} + 42 \, {\left (d x + c\right )}^{\frac {5}{2}} D a b d^{37} + 21 \, {\left (d x + c\right )}^{\frac {5}{2}} C b^{2} d^{37} - 280 \, {\left (d x + c\right )}^{\frac {3}{2}} D a b c d^{37} - 140 \, {\left (d x + c\right )}^{\frac {3}{2}} C b^{2} c d^{37} + 1260 \, \sqrt {d x + c} D a b c^{2} d^{37} + 630 \, \sqrt {d x + c} C b^{2} c^{2} d^{37} + 35 \, {\left (d x + c\right )}^{\frac {3}{2}} D a^{2} d^{38} + 70 \, {\left (d x + c\right )}^{\frac {3}{2}} C a b d^{38} + 35 \, {\left (d x + c\right )}^{\frac {3}{2}} B b^{2} d^{38} - 315 \, \sqrt {d x + c} D a^{2} c d^{38} - 630 \, \sqrt {d x + c} C a b c d^{38} - 315 \, \sqrt {d x + c} B b^{2} c d^{38} + 105 \, \sqrt {d x + c} C a^{2} d^{39} + 210 \, \sqrt {d x + c} B a b d^{39} + 105 \, \sqrt {d x + c} A b^{2} d^{39}\right )}}{105 \, d^{42}} \]
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Timed out. \[ \int \frac {(a+b x)^2 \left (A+B x+C x^2+D x^3\right )}{(c+d x)^{5/2}} \, dx=\int \frac {{\left (a+b\,x\right )}^2\,\left (A+B\,x+C\,x^2+x^3\,D\right )}{{\left (c+d\,x\right )}^{5/2}} \,d x \]
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